What Is Cross Sectional Area Of A River
The cross sectional area of channel a is 20m2and its wetted perimeter is 14m so its hydraulic radius is 1 4.
What is cross sectional area of a river. For channel b the cross sectional area is 16m2and its wetted perimeter is 12m meaning that its hydraulic radius is 1 3. Cross sectional area width x average depth m2. Cross sectional area m2 width m mean depth m cross sectional area m 2 width m mean depth m so in order to calculate discharge we must measure width depth and velocity.
Multiply the depth by the width to find the cross sectional area. Cross sectional area csa m2 this is a simple calculation to measure the amount of water at each site the cross sectional. Download an image of your cross section and print the data calculations used to construct and analyse it.
Enter your river data to quickly make a river cross section and calculate the cross sectional area wetted perimeter and hydraulic radius. Measure the depth and the width of the river. Channel a has the larger hydraulic radius so it s the more efficient channel.
Discharge area x velocity. Producing a cross section of a river channel is a basic river fieldwork skill. Whether you need to find the discharge or examine the profile of a feature such as a meander or riffle it will be necessary to produce a cross section of the river.
Braided channel cross sections can be created by entering land as negative data. What is cross sectional area of a river answers it is something that is timesed by the type of water added to the weight of the the person breathing on it. For example assume a river is 4 metres deep and 5 metres wide in one area.
Start from one river bank and move at 30cm intervals across the river. The usgs uses numerous methods and types of equipment to measure velocity and cross sectional area including the following current meter and acoustic doppler. In general river discharge is computed by multiplying the area of water in a channel cross section by the average velocity of the water in that cross section.